| Category | Difficulty | Likes | Dislikes |
|---|
| algorithms | Easy (78.41%) | 580 | - |
Tags
two-pointers | string
Companies
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编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 s 的形式给出。
不要给另外的数组分配额外的空间，你必须**原地修改输入数组**、使用 O(1) 的额外空间解决这一问题。
示例 1：
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| 输入：s = ["h","e","l","l","o"]
输出：["o","l","l","e","h"]
|
示例 2：
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| 输入：s = ["H","a","n","n","a","h"]
输出：["h","a","n","n","a","H"]
|
提示：
1 <= s.length <= 105s[i] 都是 ASCII 码表中的可打印字符
Discussion | Solution
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| class Solution {
public:
/*
* ## 解题思路
* * 双指针法
*/
void reverseString(vector<char>& s) {
int l = 0, r = s.size()-1;
while(l<r) {
swap(s[l++], s[r--]);
}
}
};
void swap(char& a, char& b) {
a ^= b;
b ^= a;
a ^= b;
}
|